<center>![IMG_20180609_174736_778.JPG](https://cdn.steemitimages.com/DQmQtqHDpCyNPaw9bqtwJAHR1iJcb4S8SUzQgXFGvVtBaAD/IMG_20180609_174736_778.JPG)</center>

Mathematics is life, not everyone knows this. Ever wondered why it's made compulsory when you pass through school? You can't escape it because you perform some arithmetics in every day.

Today's tutorial will be on COMBINATION.

#Now, What is COMBINATION?

COMBINATION is the several possible ways in which a set or number of things can be selected or chosen.

[Click here](https://steemit.com/steemstem/@hayzeed/mathematics-tutorial-on-permutation) to read the tutorial on permutation because we will still use some formulae and simplification here which might new to you.

The keywords to note is that in permutation we are arranging while the combination is selecting.

In a permutation, an order is very important, that is ABC, ACB, BAC, BCA, etc are a different arrangement. But in COMBINATION, an order is irrelevant, for ABC, ACB, BAC, BCA, etc are the same selections.

Generally, the number of combination of selecting r objects from a distinct( same) objects is denoted by;

![combination formular.png](https://cdn.steemitimages.com/DQmPuum5FzrxQEn1qvX3QEnGta3Fiqq3wZE3xYraPVcknmT/combination%20formular.png)

Where,
**_n= number of distinct objects_**
**_r= the number of objects to be selected from n_**

Let's try some examples,

Example 1: In how ways can three men be chosen from eight men?

Having read the question, you can see that we are to select not arranging. Do you agree with that? If no, read the question again.

**Solution**

n= 8
r= 3

Substituting values of n and r in the formula

We will have,

![example 1.png](https://cdn.steemitimages.com/DQmUFr2kHYkm8LUUmmcRJG8eqn7zscqCgPBbL4vDAzvSwZe/example%201.png)

The number of ways to select 3 men from 8 men is 56ways.

Do you understand what we just did? if no, go through the question and solution again.

Example 2: In how many ways can three men and two women can be chosen from six mean and four women?

Solution

There are 6 men out of which 3 will be chosen. This can be done in 6C3 ways. Also, there are 4 women out of which 2 will be chosen and it can be done in 4C2 ways.

Hence the number of ways in which 3 men and  2 women can be chosen from 6 men and four women are,

![example 2.png](https://cdn.steemitimages.com/DQmdTGVmY9py4XhMsX8ng6rZ5vySJ9ejZWvjnxMKFm7E7pV/example%202.png)
Therefore, there are 120 ways of choosing three men and two women from six men and four women.

Is it clear?




Example 3: A party of 4 or more to be selected from 10 persons, how many ways can this be done?

Solution

Having read the question, what is the number of persons to be selected from 10 persons?

You can see that 4 or more was stated in the question.

The number to be selected is 4, 5, 6, 7, 8,  9, 10

n= 10
r=4,5,6,7,8,9,10
i.e
![comb 3.png](https://cdn.steemitimages.com/DQmQvMZUvLY3TjRenz7QvB3fweBiKUKePbCZSgNYgzGBzFJ/comb%203.png)
By simplifying the terms one another,
![example 4.png](https://cdn.steemitimages.com/DQmZQhxGj7w8znboT1Z8DcLAW9woRPJeEZFDeXrAxrmGajR/example%204.png)

Therefore, the number of ways is
  = 210 +252+210+120+45+10+1=848 ways

I believed you have understood it. 

Now try these questions ;
![IMG_20180614_045800_156.JPG](https://cdn.steemitimages.com/DQmd2DK8fyDTiPQQeekcB38fsGekyVVof55rA3eEpVCivvM/IMG_20180614_045800_156.JPG)

**b** **How many committees of five can be formed from 8 men and 4 women if each committee is to have at least 2 women?**


## If you have any questions, please drop them in the comment section.

 ## Solution of the exercises will be posted in my next post
### Pictures: All pictures used in this post was created by me using math editor app.

Follow @hayzeed and visit my blog daily for more tutorial.

You can also read:

[Explanation on how 0!=1](https://steemit.com/steemstem/@hayzeed/explanation-on-why-0-1)


## References
[ Betterexplained- Combination](https://www.google.com.ng/url?sa=t&source=web&rct=j&url=https://betterexplained.com/articles/easy-permutations-and-combinations/&ved=2ahUKEwjh38nn_MbbAhWmKMAKHYH-CQsQFjAiegQIBxAB&usg=AOvVaw17IQO2fjRc1_VdirZTVCoi)
[ Wolfram - Combination](https://www.google.com.ng/url?sa=t&source=web&rct=j&url=http://mathworld.wolfram.com/Combination.html&ved=2ahUKEwjh38nn_MbbAhWmKMAKHYH-CQsQFjAnegQIBRAB&usg=AOvVaw35lzkXfMainBKyHdHqH4wn)