<html> <h2>Divisibility Rules - Telling Right Away if A Number is Divisible by 2, 3, 4, 5, 6, 9 and 10</h2> <p>Divisible means a number completely divide another number and gives zero remainder. We can tell very easily that if 2 or 3 or 5 will completely divide a given number without doing the long division. </p> <p>https://s-media-cache-ak0.pinimg.com/736x/ba/77/de/ba77de208a9629f97d3a914085c91304.jpg</p> <p><a href="https://s-media-cache-ak0.pinimg.com/736x/ba/77/de/ba77de208a9629f97d3a914085c91304.jpg">Image Source</a></p> <p><br></p> <p>Below are the Divisibility Rules (tests) starting at the test for divisibility by 2 and ending at test for divisibility by 10:</p> <ol> <li><strong>Divisibility test for 2:</strong> Any number with <strong>0, 2, 4, 6, 8</strong> at their ONES PLACE is divisible by 2. For example; numbers <strong>228</strong>, <strong>1594</strong>, <strong>5002</strong> and <strong>1170</strong> have <strong>8</strong>, <strong>4</strong>, <strong>2</strong> and <strong>0</strong> at their ONES PLACE respectively, hence all of these numbers are divisible by <strong>2</strong>. </li> <li><strong>Divisibility test for 3: Add</strong> all the <strong>digits</strong> of the given number and if the <strong>sum</strong> is divisible by three then the given number is also divisible by three. Consider there is a number 7023. To test for divisibility by 3 add all the digits of the number <strong>(7 + 0+ 2 + 3 =12)</strong>,we get 12 as the sum of digits and which is divisible by 3, hence the given number <strong>7023</strong> is divisible by<strong> 3.</strong></li> <li><strong>Divisibility test for 4:</strong> Look at the TENS and ONES digit of the number to get a two digit number and if this number is divisible by 4 then the given number is divisible by 4. For example; consider the given number is 25424 and the TENS and ONES digits (last two digits at far right) make 24 and which is divisible by 4, hence <strong>25424</strong> is divisible by<strong> 4</strong>. </li> <li><strong>Divisibility test for 5:</strong> If the ONES digit of the given number is <strong>“0”</strong> or <strong>“5”</strong> then the number is divisible by 5. For example; consider the given number is 30085, as the ones digit is 5, hence <strong>30085</strong> is divisible by <strong>5</strong></li> <li><strong>Divisibility test for 6:</strong> A given number is divisible by <strong>"6"</strong> only if it is divisible by both <strong>"2"</strong> and <strong>"3"</strong>. Consider the given number is 516. This number is divisible by 2, as the ONES digit is 6 which is divisible by 2. Now add the digits (5 + 1 + 6 = 12) to get 12 and which is divisible by 3, hence the number 516 is divisible by 3 too. As <strong>516</strong> is divisible by both <strong>2</strong> and <strong>3</strong> hence it is divisible by <strong>6</strong> as well.</li> <li><strong>Divisibility test for 9:</strong> Add all the digits of the given umber and if the sum is divisible by 9 then the number is divisible by 9. Divisibility tests for 3 and 9 are identical.</li> <li><strong>Divisibility test for 10:</strong> Simplest of all. Look at the ONES digit of a number and if it is zero then this number is divisible by 10. For example; <strong>350</strong> has <strong>“0”</strong> at ONES place, hence it is divisible by 10. </li> </ol> <p>There are divisibility rules for 7 and 8 as well but I think that's too much. If students in grade 6 or 7 just know the divisibility by 2, 3, 5 and 10 they can achieve very good marks and be very successful in higher grades math.</p> </html>
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