Here is function written in Matlab:
### Test Script:
``` 
for x = 1:100
    disp(fizzbuzz(x));
end
```

### Function:
```
function output = fizzbuzz(n)
% fizzbuzz(n) returns 'Fizz' if n is a multiple of 3, 
% 'Buzz' if n is a multiple of 5, 'FizzBuzz' if n is a 
% multiple of 5 and 3, and returns n if it is neither a 
% multiple of 3 or 5.
% Format of Call: fizzbuzz(n);
% Returns: output = 'Fizz', 'Buzz', 'FizzBuzz', or n 
% based on if n is a multiple of 3 or 5
    
    if ~isnumeric(n)
        error('Error: Input must be a number, not a %s.',class(n));
    else
        output = '';
        if rem(n,3) == 0
            output = 'Fizz';
        end
        if rem(n,5) == 0
            output = strcat(output,'Buzz');
        end
        if strcmp(output,'')
            output = num2str(n);
        end
    end
```
### Console Output
```
1
2
Fizz
4
Buzz
Fizz
7
8
Fizz
Buzz
11
Fizz
13
14
FizzBuzz
16
17
Fizz
19
Buzz
Fizz
22
23
Fizz
Buzz
26
Fizz
28
29
FizzBuzz
31
32
Fizz
34
Buzz
Fizz
37
38
Fizz
Buzz
41
Fizz
43
44
FizzBuzz
46
47
Fizz
49
Buzz
Fizz
52
53
Fizz
Buzz
56
Fizz
58
59
FizzBuzz
61
62
Fizz
64
Buzz
Fizz
67
68
Fizz
Buzz
71
Fizz
73
74
FizzBuzz
76
77
Fizz
79
Buzz
Fizz
82
83
Fizz
Buzz
86
Fizz
88
89
FizzBuzz
91
92
Fizz
94
Buzz
Fizz
97
98
Fizz
Buzz
```

The general design is to take the input value, check to be sure it's a number, then proceed to construct the output. Since 'FizzBuzz' is the combination of 'Fizz' and 'Buzz' it made sense to me to build the output string starting with an empty string and adding 'Fizz' if n is divisible by 3 followed by 'Buzz' if n is divisible by 5. Since they are concatinated into the empty string, 'FizzBuzz' logically follows if n is divisible by 3 and 5. Finally, if nothing was added to the output string then it must not have been divisible by either, so I assign a string form of n to the output.

I'm curious to see how far off I am from best practices for this challenge.