RE: Introducing the Coding Challenge by tzs

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coding-challenge · @tzs · Aug 18 '17

$0.78

Two solutions with Haskell: http://codepad.org/tIR16emr

![Screen Shot 2017-08-17 at 9.21.12 PM.png](https://steemitimages.com/DQmed9LTNRtgUqf7jqWYbpWGJUWmUaRt4XXJePTmYzSJ6Zd/Screen%20Shot%202017-08-17%20at%209.21.12%20PM.png)

👍 reggaemuffin, tzs, benniebanana

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@reggaemuffin · Aug 18 '17

$0.03

Thank you for your submission! I really hoped that I get a Haskell one 🐑

Your first solution is pretty concise, not much to say there. The second one is really cool! Abstracting it as rules is smart and that filter reduces logic duplication. 

I think you can make this a bit more readable with making rules a constant and extracting the tester in a helper function that has a good name. 

Looking forward to you writing a post on how your process was, implementing the second version of it.

👍 tzs

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@ratticus · Aug 18 '17

$0.03

Only comment I have is the question asked for 0 to 100 but the solutions are for 1..100. How does either solution work for 0? Dealing with 0 shouldn't be too difficult, though 0/x is going to be 0 and 0 mod x is also 0. I guess it will/should print FizzBuzz for n=0.

👍 tzs

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@reggaemuffin · Aug 18 '17

True his solution starts at 1, good catch, here is a tip! But yeah it will work with 0, pretty sure.

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@tipu · Aug 18 '17

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@tzs · Aug 18 '17

Check this one: [http://codepad.org/GPTa3Tgm](http://codepad.org/GPTa3Tgm)

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@tzs · Aug 18 '17

I don't know what you mean by
> making rules a constant

It's already a constant there.

Since the filter phrase used once and it's a short one, I'd argue it's easier to read it this way.

I implemented/borrowed the second one because I wanted to have a generic solution that is easy to expand or change with new `rules`. Now, all you need is to update the `rules` to get a new `FizzBuzz`.

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