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RE: Issues With Using Stake To Filter Content by carn

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Viewing a response to: @doodlebear/re-greer184-issues-with-using-stake-to-filter-content-20180219t134358984z

· @carn · (edited)
$0.15
You can create as many accounts as you want if you fund them with SP. The phone number/IP thing is just for free accounts. You can also create accounts through an API or SteemConnect ([tutorial for SteemConnect](https://steemit.com/news/@timcliff/new-tool-from-busy-org-create-new-steem-blockchain-accounts-with-steemconnect))

I currently own this account plus two others (@steemitbooks and @shadeslayer) and I've also created one for a friend.
👍  
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vote details (1)
@doodlebear ·
thx for the info! The creation of theme-based resteem bots would require to creat dozens of them, which makes it very expensive. The way via different IPs/Tels is the affordable way to do so. 

I didn't know about the Steemconnect way of creating an account, is it for free and can you create multiple accounts with it?
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@carn ·
$0.02
The Steemconnect way is just like the way normal accounts are created but more accessible since you don't need to run any code. The only cost is the Steem or SP delegation that the new account needs. You don't ever lose any Steem, it just gets transferred to your new account. You can create unlimited accounts this way (all of the accounts I mentioned were created that way)

Steemit requires phone verification because they have to create accounts the same way (they are "paying" the registration fee with their delegation) and they don't want to pay for your secondary accounts.
👍  
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@doodlebear ·
So.. I only have to provide enough Steem Power as delegation, but I don't have to pay money? If I understand the tutorial correctly, it costs quite a bit:

> Go to https://steemd.com/ and find the current value for account_creation_fee. Multiply the value by 30. Put this amount in for STEEM. (At the time of writing this post, the account creation fee is 0.5 STEEM, so "15.000 STEEM" goes into that field.)

I don't find this *account_creation_fee*... can you direct me there, please?
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