Viewing a response to: @rycharde/re-sinochip-re-rycharde-brainsteem-mathematics-challenges-fibonacci-2018-20180307t135421266z
As the smallest b satisfying the condition of 13b-2 diviaible by 21 is 5. 5+21n where n=0,1,... will also satisfy the condition of b. Followong this logic, we can fond the first pair of a and b such that a < b , which is when a = 20 and b = 47. In such case, a + b is 67. Also, the next possible value of b is 47 + 21 = 68 which is greater than the above a + b. Therefore, the smallest possible value of a + b is 67.
| author | sinochip |
|---|---|
| permlink | re-rycharde-re-sinochip-re-rycharde-brainsteem-mathematics-challenges-fibonacci-2018-20180307t153353219z |
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| author | rycharde |
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| permlink | re-sinochip-re-rycharde-re-sinochip-re-rycharde-brainsteem-mathematics-challenges-fibonacci-2018-20180307t164003757z |
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In fact, with the additional condition of a < b, 20 and 47 is the only possible pair of a and b
| author | sinochip |
|---|---|
| permlink | re-rycharde-re-sinochip-re-rycharde-re-sinochip-re-rycharde-brainsteem-mathematics-challenges-fibonacci-2018-20180307t164931510z |
| category | mathematics |
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Yes :-) I made this question myself - the sequence is just an excuse to create the Diophantine equation, which I knew was a pain to solve, given the fairly small numbers. Thanks a lot for taking part.
| author | rycharde |
|---|---|
| permlink | re-sinochip-re-rycharde-re-sinochip-re-rycharde-re-sinochip-re-rycharde-brainsteem-mathematics-challenges-fibonacci-2018-20180307t170330901z |
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