Viewing a response to: @ninahaskin/re-quantumdeveloper-2019109t3111958z
Looks good. By the way 4d-volume wouldn't be too hard to calculate: The 2D-volume of a square is V₂ = A = a². The 3D-volume of a cube is V₃ = a³. →The 4D-volume of a tesseract is V₄ = a⁴. Although its so counterintuitive to make sense of these higher dimensions, the math of it is mostly as easy as for the lower dimensional counterpart.
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