Viewing a response to: @mobi72/pzaf5s
That's wrong. There are two solutions for `4nĀ² - 2n - 1 = 0` They just aren't integers, that's why you didn't find them.
| author | quantumdeveloper |
|---|---|
| permlink | pzazef |
| category | puzzle |
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Hahaha ... It gets interesting ... My mathematical skills got rusty. I didn't even think about the quadratic formula, last time used it in mid 90's, I think. Two solutions are `(1+sq.rt(5))/4 & (1-sq.rt(5))/4` where, a = 4, b = -2 & c = -1
| author | mobi72 |
|---|---|
| permlink | pzb1lx |
| category | puzzle |
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