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HERON'S FORMULA computing by meta007

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· @meta007 · (edited)
$7.10
HERON'S FORMULA computing
Hello math bugs(🐞) and hivers(🐝)
I hope you are strong and stout & doing well in life.


Well come to another interesting geometric proof. We all know about Heron's formula used to find area of a triangle when three sides of it are given. I'll show you today how to drive it.

![](https://images.ecency.com/DQmP8RqR1sdZQwupxb2fEenQ7fJ2f5xGGtQ9kT1KHjBdjH5/addtext_06_09_04.39.23.png)

To prove it we need to know formula of **Pythagoras** and to do a little construction. At first, let's draw a perpendicular from a vertex to its opposite side of the ∆"*ABC**. Here I draw **AD** which os perpendicular to **BC**. Suppose, the three sides **a**, **b** , **c** are opposite to the respective angles **A**, angle **B** and angle **C** and also **BD**= x and **CD**= (a-x). Check details in the following figure:

![](https://images.ecency.com/DQmbCLqXqmEpMfVmGPAdfVRwL4WtAT2P72G4rNieQH9PHf9/addtext_06_12_10.17.40.png)

**Now we gonna use Pythagoras' formula in each of the smaller triangle namely** ∆**ABD** and ∆**ACD**. In case ∆ABD , we can say c² = x² + h² or h² = c² - x². Check the follwoing figure also:

![](https://images.ecency.com/DQmQmndncvnHZDKFKRYUE65AEtSQGUQcYvHTYV6s2FJ4ojk/addtext_06_12_10.42.24.jpg)

From ∆**ACD** , we also can get b² = (a-x)² + h² or h² = b² - a² -x² + 2ax. Check it below:


![](https://images.ecency.com/DQmQD1f1FmdKi9hNLcPLeb65xb3wQ5UVUZU8d7JNee8136q/addtext_06_14_08.02.45.jpg)

Check Heron's formula carefully. As there is no **x** or **h** in it. The the formula is given by **a**, **b** and **c** only. To get rid of **h** we need to compare equation1 and equation2  and we can have the value of **x**. Check the following figure:

![](https://images.ecency.com/DQmZ6iAD6GdM2Ee2xdATYbageyJ2BzAkqUuA8mJbi5wX7aT/addtext_06_14_08.47.32.jpg)


See, our moto is to get rid other variables except **a**, **b**, and **c**. What can we do now! If we replace the value of x in equation1 or 2, we will have an equation devoid of unwanted variables. As equation1 is simplier than equation2, we gonna use the former. Check the figure below:

![](https://images.ecency.com/DQmeMKUNKcDxxok7qoUaqyWvbsNbs9LeVbZxLcaBRomAx5W/addtext_06_14_10.13.59.png)

We know the area of a triangle is given by 1/2 ×base × height.  Here we have consider **a** as base and height **h**. Once we find vaule of **h** from above equation, problem is solved because the vaule of **h** we gonna obtained will be in terms of three sides( a,b & c) of the ∆ABC. let's get it done.


![](https://images.ecency.com/DQmUT89hpPAwNvXFRguvkaB7qRTRNEfo7wwGCuryHp8qrie/addtext_06_14_10.48.24.jpg)
Now area will be 1/2× base × height =1/2× a×√(S(S-a)(S-b)(S-c) unit². Also check the following figure:


![](https://images.ecency.com/DQmbn8u5nnckHmKgs82kaNFwvhbuWGV6jiZNkBBH9F7Fw2b/addtext_06_14_11.09.03.jpg)

**All the figures and images are made by me using android application.**

Please ignore the silly mistake(s) of there is any. All the figures you have seen take huge time to build. So re-editing hurts.

I hope you find this post interesting ans effortful. Thank you so much for visiting. 

Have a good day. 

All is well.

Regards: @meta007
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@discovery-it ·
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@enforcer48 ·
The tough part here is keeping track of all the variables. Gotta love math sometimes.

!discovery 41
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@meta007 ·
$0.07
Yeah there are a lot of variables and all should be taking care of at the same time. Good to know that you love math sometimes. The same goes for me 😄😄.

Thanks man for visiting 
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@gabrielr29 ·
I keep thinking of Galileo Galilei's phrase when mathematics is taught with passion: "Mathematics is the language with which God wrote the universe".

I love it when someone shares their knowledge with passion and fervor. I wish you much success. The images didn't load very well but it could be because of my internet, it is very deficient here.
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@meta007 ·
Yeah it's a wonder. It seems the universe is like a balanced equation of mathematics. 

As for image, it may be the app. issue.

Thanks man for encouraging and supporting.
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